In fig , O is the centre of the circle and angle OBA=60 degree, then find angle ACB.

Q. In fig, O is the centre of the circle and angle OBA = 60°, then find angle ACB.

          

Dear Student,

OA and OB is the radius of the circle.So, OA=OBGiven:OBA=60°Since, OA=OB, OBA=OAB=60°In AOB,AOB+OBA+OAB=180°AOB=180°-60°+60°AOB = 60°The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.Therefore, AOB=2ACBACB = 12AOBACB = 12×60°ACB = 30°

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