In figure,a circle with center O is drawn and angle=50° . Find x
Q. 
In figure, a circle with centre O is drawn and  ∠BAC =50° . Find x ?

Dear student

Clearly,BOC=2BAC    {By angle at centre theorem]BOC=100°Since OB=OC   [radius of circle]So, OBC=OCB   ...(1)Now, In BOC by angle sum property of triangleBOC+OBC+OCB=180°100°+2OBC=180°      [from 1]OBC=40°=OCBSo, x=40°
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Thanks bro
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Here angle bac is 50, so angle boc will be 100 now ob and oc are equal radius so, x will be 40.Ans is x is 40.
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