In how many ways can 5 person travel in a car, 2 including driver in the front seat and 3 in the back seat if 2 particular person out of five do not know driving?

It is given that, 5 persons can travel in a car. and out of them 2 didn't know driving.

So, there seating arrangement can be done as:

Number of persons who know driving = 3

Therefore, on driver seat out of 3 persons, 1 person can sit in 3C1 ways.

Now, 4 passenger seats were vacant in the car and in those seat any of the 4 person can seat in 4! ways.

Therefore, total number of ways in which 5 persons can travel in a car = 4! × 3C1

= 4 × 3 × 2 × 3 = 72

  • 7

 It is given that, 5 persons can travel in a car. and out of them 2 didn't know driving.

So, there seating arrangement can be done as:

Number of persons who know driving = 3

Therefore, on driver seat out of 3 persons, 1 person can sit in 3C1 ways.

Now, 4 passenger seats were vacant in the car and in those seat any of the 4 person can seat in 4! ways.

Therefore, total number of ways in which 5 persons can travel in a car = 4! x 3C1

= 4 x 3 x 2 x 3 = 72

  • 22
It is given that, 5 persons can travel in a car. and out of them 2 didn't know driving. So, there seating arrangement can be done as: Number of persons who know driving = 3 Therefore, on driver seat out of 3 persons, 1 person can sit in 3C1 ways. Now, 4 passenger seats were vacant in the car and in those seat any of the 4 person can seat in 4! ways. Therefore, total number of ways in which 5 persons can travel in a car = 4! x 3C1 = 4 x 3 x 2 x 3 = 72
  • 5
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