In how many ways can 7 books be arranged on a shelf if
1) there is no restriction
2) 3 particular books always stand together
3) 2 particular books must occupy the ends.
Dear Student,
1) If there is no restriction then the total arrangements is given by 7!= 5040 .
2)If three Particular books are to be together we make one packet of those three books, and thus the packet along with remaining 4 books can be arranged in 5! ways= 120 , and within the packet the three books can be arranged in 3!=6 ways
so total number of such arrangements= 120x6= 720
3) If 2 particular books to occupy end places, this can happen in 2! ways=2 ways, then rest of the 5 books can be arranged in 5! ways=120 ways, so total number of such arrangements are 2x120=240 ways
Hope this clears your doubt
With regards
1) If there is no restriction then the total arrangements is given by 7!= 5040 .
2)If three Particular books are to be together we make one packet of those three books, and thus the packet along with remaining 4 books can be arranged in 5! ways= 120 , and within the packet the three books can be arranged in 3!=6 ways
so total number of such arrangements= 120x6= 720
3) If 2 particular books to occupy end places, this can happen in 2! ways=2 ways, then rest of the 5 books can be arranged in 5! ways=120 ways, so total number of such arrangements are 2x120=240 ways
Hope this clears your doubt
With regards