in ideal solution of non volatile solute B and solvent Ain 2 :5 molar ratio has vapour pressure 250 mm. if a another solution in ratio 3:4 prepared then vapour pressure above this solution
1) 200 mm
2) 250 mm
3) 350 mm
4) 400 mm
In first case molar ratio of solute and solvent is 2:5
So mole fraction of solvent,
Using Raoult's law:
p(solution) = p(pure solvent) mole fraction of solvent
250 = p(pure solvent) 0.71
p(pure solvent) = 352.11 mm
In second case molar ration of solute and solvent is 3:4
So mole fraction of solvent,
Using Raoult's law:
p(solution) = p(pure solvent) mole fraction of solvent
p(solution) = 352.11 0.57 = 200.7 mm
Hence correct option is 1) 200 mm
So mole fraction of solvent,
Using Raoult's law:
p(solution) = p(pure solvent) mole fraction of solvent
250 = p(pure solvent) 0.71
p(pure solvent) = 352.11 mm
In second case molar ration of solute and solvent is 3:4
So mole fraction of solvent,
Using Raoult's law:
p(solution) = p(pure solvent) mole fraction of solvent
p(solution) = 352.11 0.57 = 200.7 mm
Hence correct option is 1) 200 mm