-in maths test two representatives while solving a quadratic equation comitted following mistakes
- one of them made a mistake in constant term and got the roots 5 and 9
- another one committed an error in the coefficient of x and got the roots as 12 and 4 find the equation
-
Dear Student,
Please find below the solution to the asked query:
Given : While solving a quadratic equation committed mistakes
1 ) One of them made a mistake in constant term and got the roots 5 and 9 , So
Our equation = ( x - 5 ) ( x - 9 )
x2 - 5 x - 9 x + 45
x2 - 14 x + 45 , Here " 45 " is wrong
2 ) One of them made a mistake in coefficient of x and got the roots 12 and 4 , So
Our equation = ( x - 12 ) ( x - 4 )
x2 - 4 x - 12 x + 48
x2 - 16 x + 48 , Here " - 16 " is wrong
So,
Our right equation = x2 - 14 x + 48 ( Ans )
Hope this information will clear your doubts about quadratic equation .
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query:
Given : While solving a quadratic equation committed mistakes
1 ) One of them made a mistake in constant term and got the roots 5 and 9 , So
Our equation = ( x - 5 ) ( x - 9 )
x2 - 5 x - 9 x + 45
x2 - 14 x + 45 , Here " 45 " is wrong
2 ) One of them made a mistake in coefficient of x and got the roots 12 and 4 , So
Our equation = ( x - 12 ) ( x - 4 )
x2 - 4 x - 12 x + 48
x2 - 16 x + 48 , Here " - 16 " is wrong
So,
Our right equation = x2 - 14 x + 48 ( Ans )
Hope this information will clear your doubts about quadratic equation .
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards