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In page 148 Qn. 3

BD and CE are altitudes of Triangle ABC such that BD=CE.

1. State the 3 pairs of equal parts in triangles CBD and BCE ?

2. Is triangle CBD congruent to triangle BCE?

3. Is Angle DCB=Angle EBC ?

Please find below the solution to the asked query:

From given information we form our diagram , As :

Here , BD and CE are altitude , So $\angle $ CED = $\angle $ BDC = 90$\xb0$ --- ( 1 )

1 ) 3 pairs of equal parts in triangles CBD and BCE :

BD = CE ( Given )

$\angle $ BDC = $\angle $ CED = 90$\xb0$ ( From equation 1 )

And

BC = BC ( Common side )

2 ) $\u2206$ CBD $\cong $ $\u2206$ BCE ( By RHL rule )

3 ) $\angle $ DCB = $\angle $ EBC ( By CPCT )

Hope this information will clear your doubts about Congruence of Triangles.

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