In ∆PQR,PM perpendicular to QR. If PM.PM=QM.MR Prove:: Angle QPR=90° Share with your friends Share 0 Ashwini Kumar answered this We have, PM.PM=QM.MR⇒PMRM=QMPMAnd ∠PMQ=∠RMP=90°∴△PMQ~△RMP By SAS similarityNow ∠QPM=∠PRM=θ (say)And ∠PRM+∠MPR=90°⇒∠MPR=90°-∠PRM=90°-θNow,∠QPR=∠QPM+∠MPR=θ+90°-θ=90° -2 View Full Answer