in Q.1 answer is 4 but how is it possible since all other than (BO3^3- ) do not have electron to enite ? explain
Dear Student,
Flame is produced due to electron transitions from excited state to normal state. Electrons get excited due to heat energy from the flame. When they go back to the ground state, they release electromagnetic energy which may have a characteristic colour.
Inner shell electrons can take part in the transitions too.
From the given options, all except Al3+ and Mg2+ show characteristic colours under the flame test.
It is generally shown by s-block elements, though magnesium s an exception.
Thus, the correct answer is four.
Hope this information will clear your doubts about this topic.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
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Flame is produced due to electron transitions from excited state to normal state. Electrons get excited due to heat energy from the flame. When they go back to the ground state, they release electromagnetic energy which may have a characteristic colour.
Inner shell electrons can take part in the transitions too.
From the given options, all except Al3+ and Mg2+ show characteristic colours under the flame test.
It is generally shown by s-block elements, though magnesium s an exception.
Thus, the correct answer is four.
Hope this information will clear your doubts about this topic.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
Also CLICK HERE and check out the POWER TIPS for JEE Advanced 2017.
Regards