# In the adjoining figure, ABCD is a rhombus and DCFE is a square, if ∠ABC = 56°, find  (i) ∠DAG                 (ii) ∠FEG                 (iii) ∠GAC                  (iv) ∠AGC [Hint. (i) ∠EDA = 90° + 56° = 146°, ED = AD.]

Each angle of square is 90 and rhombus is basically a parallelogram so its opposite  angles would be equal  and sum of co interior angles sum is 180.Now you can proove it
• -2
In a adjoining figure abcd is a square and dfeb is a rhombus cdf
• -1
what is rhombus
• 0
In the adjoining figure ,ABCD is a rhombus and DCEF is a square . If angle ABC =56 degree find angle DAG and Angle FEG and angle AGC
• -4
What are you looking for?