In the adjoining figure AD is the median of triangle ABC and DE parallel BA so that BE is the - Maths - Quadrilaterals

Question

In the adjoining figure AD is the median of triangle ABC and DE
parallel BA so that BE is the also a median of triangle ABC

Rohit Brahme · Answer

Since AD is the median of ΔABC, then BD = DC

Given, DE || AB and DE is drawn from the mid point of BC i e D,
then by converse of mid-point theorem,

it bisects the third side which in this case is AC at E

Therefore, E is the mid point of AC

Hence, BE is the median of ΔABC

In the adjoining figure AD is the median of triangle ABC and DE parallel BA so that BE is the also a median of triangle ABC