In the adjoining figure PQ and PR are tangents from P to a circle with centre O. If angle POR = 55 find angle QPR.

I think I found the answer:
In triangle POR,
angle ORP = 90 ( tangent is perpendicular to radius )
angle POR = 55 (given)
angle OPR = 180-90+55 = 35
OP bisects angle QPR
=> angle QPR = 2(angle OPR)
​angle QPR = 70
 
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