In the adjoining isosceles trapezium ABCD, ∠ c=102 ° .Find all the remaining angles of the trapezium. Share with your friends Share 5 Varun.Rawat answered this We have ABCD as the trapezium in which DC∥AB and AD = BC.So, ABCD is an isosceles trapezium.Since, DC∥AB, and CB is a transversal, then ∠C + ∠B = 180° Sum of consecutive interior angles on same side of transversal is 180°⇒102° + ∠B = 180°⇒∠B = 180° - 102°⇒∠B = 78°We know that angles on the either sides of bases of isosceles trapezium are of same measure.So, ∠A = ∠B and ∠D = ∠CNow, ∠A = 78° and ∠D = 102° 9 View Full Answer Tanisha answered this answer 3
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