In the Binomial Expansion of (2x2+x-3)6 , find the coefficient of x^11.

2x2+x-36=2x2+3x-2x-36=x2x+3-12x+36=2x+36x-16So x11 will be obtained by multiplying the coefficient of x6 of 2x+36 to x5 of x-16and vice-versa.Tr+1=nCr xn-r ar  for x+anSo for here the x11=6C0×2x6-0×30×6C1×x6-1×-11+6C1×2x6-1×31×6C0×x6-0×-10=-26×6x11+18×25x11=576-384x11=192x11So 192 is the answer

  • 47
What are you looking for?