in the chapter trigonometric functions, exercise 3.3, Q12, how did (2 sin 5x cos x ) (2 cos 5x sinx) change to (2 sin5x cos 5x)(2 cosx sinx)??? and  pls. also explain ..how did we get the answer same as the R.H.S.?

(2sin5xcosx).(2cos5xsinx)

Rearranging the terms we get:-

=(2sinxcosx).(2sin5xcos5x)

=Sin2x.sin2(5x).           [since sin2A= 2sinAcosA]

=Sin2x.sin10x=RHS.

  • 2

thanks 

  • 0
What are you looking for?