In the circuit shown below C1 = 10 µF, C2 = C3 = 20 µF, and C4 = 40 µF. If charge on C1 is 20 µC then potential difference between X and Y is
(1) 2 V (2) 3 V (3) 6 V (4) 3.5 V
Dear student,
here c1 and c2 are in parallel
and c3 and c4 are also in parallel
and (c1,c2) and (c3,c4) are in series
let q1 , q2, q3, q4 are charges on c1,c2,c3,c4
q1/q2 = c1/c2
20/q2 = 10/20
q2 = 40 uC
total charge on positive plate of c1 and c2 = 20+40 = 60 uC
pot difference across q2 = 40/20 = 2V
resultant of c3,c4 = 20+40= 60uF
Q = 60uC
pot difference across q3 = 60/60 = 1V
pot difference between X and Y= 2V+1V = 3V
Regards.
here c1 and c2 are in parallel
and c3 and c4 are also in parallel
and (c1,c2) and (c3,c4) are in series
let q1 , q2, q3, q4 are charges on c1,c2,c3,c4
q1/q2 = c1/c2
20/q2 = 10/20
q2 = 40 uC
total charge on positive plate of c1 and c2 = 20+40 = 60 uC
pot difference across q2 = 40/20 = 2V
resultant of c3,c4 = 20+40= 60uF
Q = 60uC
pot difference across q3 = 60/60 = 1V
pot difference between X and Y= 2V+1V = 3V
Regards.