In the circuit shown below C1 = 10 µF, C2 = C3 = 20 µF, and C4 = 40 µF. If charge on C1 is 20 µC then potential difference between X and Y is


(1) 2 V                (2) 3 V                  (3) 6 V                 (4) 3.5 V

Dear student,
 here c1 and c2 are in parallel
and  c3 and c4 are also in parallel
and (c1,c2) and (c3,c4) are in series
let q1 , q2, q3, q4 are charges on c1,c2,c3,c4

 q1/q2 = c1/c2
20/q2 = 10/20
q2 = 40 uC

total charge on positive plate of c1 and  c2 = 20+40 = 60 uC
pot difference across  q2 =  40/20 = 2V

 resultant of c3,c4 = 20+40= 60uF
Q = 60uC
pot difference across  q3 = 60/60 = 1V
pot difference between X and Y= 2V+1V = 3V



Regards.

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