in the expansion (1+x) (1+x+x^2) ... (1+ x + x^2 +...+ x^2n) the sum of the coefficients is ?

Dear student 
SUm of the coefficient of any expression is obtained by putting the variable=1 in the expression. 
So if we put x=1 in the expression
 (1+x)(1+x+x2)..(1+x+x2+....x2n), we get (1+1)(1+1+1)...(1+1+1...1(2n+1times))=2.3.4......(2n+1)=1.2.3.4......(2n+1)= (2n+1)!
Hope you are clear with this 
With regards 

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