In the expansion of (1+x)34, the coeffients of the (2r+1)th and (r+2)th terms are equal. Find r?

As we know that the coefficient of r th in the expansion of (1 + x) n is n C r – 1.

 

∴ Coefficients of (r +2)th and (2r +1)th term in the Expansion of (1 + x)34 are 34C r + 1 and 34C2 r

 

It is given that these coefficients are equal

34C r + 1 = 34C2 r 

+1 = 2r 

( n C r = n CS  r = S or r + S = n)

r =1.

  • 0
What are you looking for?