# in the fig O is the centre of circle with AC =24cm and AB=7 cm. and angle BOD =90. find the area of the shaded region..NOT ABLE TO UPLOAD THE DIAGRAM....its like a circle a diamete.two semicircles are thus formed. one upper side of the diameter a triangleABC is formed with BC as its base n BC is the diameter...the on the lower side of the diameter the portion i.e the semicircle is biscetedby OD the radius... IN the triangle AB is the smallest side AB the longest n AC the shortest...pls make it as soon as possible tommorow is my maths exam...pls

and i think BCis the longest { MAY BE U HAVE MADE A MISTAKE}

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In Figure 6, O is the centre of the circle with AC = 24 cm, AB = 7 cm andBOD = 90.

Find the area of the shaded region. [Use = 3.14] Solution:

O is the centre of circle.

Given: AC = 24 cm, AB = 7 cm andBOD = 90.

The angle in a semicircle is 90.

∴ BAC = 90

So, ΔABC is a right-angled triangle. Using Pythagoras Theorem inΔABC, we have

(AC)2 + (AB)2= (BC)2

∴(24)2 + (7)2 = (BC)2

⇒(BC)2 = (576 + 49) cm2

⇒(BC)2 = 625 cm2

⇒BC = 25 cm

BC is diameter of circle. Area of the sector COD, A2 Area of circle, A3= r2 = Area of circle (Area ofΔABC + Area of sector COD)

= A3 (A1+ A2)

= 491.07 cm2 (84 + 122.77) cm2

= 491.07 cm2 206.77 cm2

= 284.30 cm2

Thus, the area of shaded region is 284.30 cm2.

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isnt pie=3.14?

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isnt pie=3.14?
• 7
No pie is not 3.14 but its 22/7
• -17
In the question..it is mentioned that we have to use pie=3.14
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Hi
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• 14
The value of pi is to be taken 22/7
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Write approx word after the final answer
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Be the best you can and do the best you can work hard so that no one can disapprove you 📚
• -7
Answer of this question is 154/3cm^2
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Pie is 3.14 and u have used 22/7 what a silly mistake...!!!!
• -1
284.30 cm2
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284.30
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Since in the question pie is given as 3.14 the most accurate answer is 283.96875
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It base on triangle phyt therom
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In Figure 6, O is the centre of the circle with AC = 24 cm, AB = 7 cm andBOD = 90.

Find the area of the shaded region. [Use = 3.14]

?

Solution:

O is the centre of circle.

Given: AC = 24 cm, AB = 7 cm andBOD = 90.

The angle in a semicircle is 90.

? BAC = 90

So, ?ABC is a right-angled triangle.

?

Using Pythagoras Theorem in?ABC, we have

(AC)2?+ (AB)2= (BC)2

?(24)2?+ (7)2?= (BC)2

?(BC)2?= (576 + 49) cm2

?(BC)2?= 625 cm2

?BC = 25 cm

BC is diameter of circle.

?

Area of the sector COD, A2

?

Area of circle, A3= r2

?

= Area of circle (Area of?ABC + Area of sector COD)

= A3?(A1+ A2)

= 491.07 cm2?(84 + 122.77) cm2

= 491.07 cm2?206.77 cm2

= 284.30 cm2

Thus, the area of shaded region is 284.30 cm2.
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