In the figure ABCD is a rectangle of length 10?2 cm and breadth 5?2 cm. If APB is an isoseles triangle inscribed in the semicircle with daimeter AB find the area of the shaded region

Dear student
Area of semi-circle=12πr2=12×π×d22=12×227×10222=5507cm2Draw PQAB.So, PQ=BC=52cmAnd, QB=AB2=1022cm=52cmSo, area of APB=12×AB×PQ=12×102×52cm=50cm2So, area of shaded region=Area of semi-circle- area of APB=5507-50=550-3507=2007 cm2

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