In the figure ABCD is a rectangle of length 10?2 cm and breadth 5?2 cm. If APB is an isoseles triangle inscribed in the semicircle with daimeter AB find the area of the shaded region Share with your friends Share 1 Lovina Kansal answered this Dear student Area of semi-circle=12πr2=12×π×d22=12×227×10222=5507cm2Draw PQ⊥AB.So, PQ=BC=52cmAnd, QB=AB2=1022cm=52cmSo, area of △APB=12×AB×PQ=12×102×52cm=50cm2So, area of shaded region=Area of semi-circle- area of △APB=5507-50=550-3507=2007 cm2 Regards -6 View Full Answer