In the figure, BL is perpendicular to AC, MC is perpendicular to LN, AL=CN and BL =CM. Prove that triangle ABC is congruent to triangle NML

AL = CN (GIVEN)
ADDING LC TO BOTH SIDES
AL + LC = LC + CN
​AC = LN
​IN ABC AND NML
AB = MN  
AC = NL
ANGLE BCA = ANGLE MLN
​ABC = NML
 
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experts can you please answer
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How ab =mn
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hypotenuse ab and hypotenuse mn of equal sides
 
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