In the figure, BL is perpendicular to AC, MC is perpendicular to LN, AL=CN and BL =CM. Prove that triangle ABC is congruent to triangle NML
AL = CN (GIVEN)
ADDING LC TO BOTH SIDES
AL + LC = LC + CN
AC = LN
IN ABC AND NML
AB = MN
AC = NL
ANGLE BCA = ANGLE MLN
ABC = NML
ADDING LC TO BOTH SIDES
AL + LC = LC + CN
AC = LN
IN ABC AND NML
AB = MN
AC = NL
ANGLE BCA = ANGLE MLN
ABC = NML