In the figure given alongside, ∠ACB = 50°, ∠DEC = 4x° and ∠ADE = 3x°.
What is the value of x?
(A) 10°                  (B) 40°                  (C) 45°                     (D) 50°

Dear Student,
In ABCA+B+C=180°   (angle sum property)A+90°+50°=180°A=180°-140°=40°Now,AED+DEC=180°     (Linear pair)AED+4x°=180°AED=180°-4x°and,In ADEA+ADE+AED=180°       (angle sum property)40°+3x°+180°-4x°=180°220°-x=180°-x=180°-220°x=40°So, option B is correct.

Hope, you will find this answer helpful.
 

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