In the figure given below, the position – time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 sec is –
(1) 0.2 kg-m/s                  (2) –0.2 kg-m/s                (3) 0.1 kg-m/s             (4) –0.4 kg-m/   

     

Dear Student ,
Here in this case at t = 0 s the velocity is 0 and at time  t =2 s the velocity is = 1/2 x 2 x 4 = 4 m/s
So the impulse at t =2 sec is = 0.1 x 4 = 0.4 m/s .

Regards

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