In the figure, if ∠APO = 40°, find ∠AOB Share with your friends Share 0 Shruti Tyagi answered this Dear Student, Since tangent at point of contact with circle is perpendicular to radius⇒∠PAO=∠PBO=90also if two tangents are drawn to circle from external point, then they are equally inclined to segment joining centre to the point⇒∠APO=∠BPO=40Also ∠APB=∠APO+∠BPO⇒∠APB=80Now AOBP is quadrilateralsum of all angles of quadrilateral is 360⇒∠PAO+∠PBO+∠AOB+∠APB=360⇒90+90+∠AOB+80=360⇒∠AOB=360-180-80⇒∠AOB=100 Regards, 1 View Full Answer Priyanshu Raj answered this 100 degree hoga 0
