In the figure p is any point on side BC of a triangle ABC. PQ||BA  and PR|| CA are drawn. RQ is extended to meet BC produced at S. Prove that SP2 =SB ×  SC.

Dear Student ,
Please find below the solution to the asked query :

PQ  BA   and   PR  CA    GivenPQ  RB   and  PR  CQ .In SBRPQ  RBBy BPTSPSB=SQSR   ... 1In SPRPR  CQBy BPTSCSP=SQSR   ... 2From 1 and 2 , we getSPSB=SCSPSP2=SB × SCHence Proved.
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