in the figure PQRS is a square ,O is the centre of the circle. If RS = 10 root 2, then find the area of the shaded region 

But how..

In ▲PQR {by pythagorus theoram}
(PR)​²=(PQ)²+(QR)²
           =(10 root 2)² + ​(10 root 2)²
           =400
PR=20cm
Diameter of cemicircle=​PR=20cm
Radius=10cm
Area=1/2×π​​×r²
        =1/2  ×22/7×10×10
         =50×π​  cm²
          Area of triangle=1/2×​base×​height
                                =1/2×​10 root 2×​10 root 2​
                                =100 cm^{2
Required Area=}50×π-​100  cm²

hope this helps u.....
                

in Math, Class X In ▲PQR {by pythagorus theoram} (PR)​2=(PQ)2+(QR)2 =(10 root 2)2 + ​(10 root 2)2 =400 PR=20cm Diameter of cemicircle=​PR=20cm Radius=10cm Area=1/2×π​​×r2 =1/2 ×22/7×10×10 =50×π​ cm2 Area of triangle=1/2×​base×​height =1/2×​10 root 2×​10 root 2​ =100 cm2 Required Area=1100/7-100 157.1-100cm2

it is 57 cm2
 

In the figure pqrs is a square o is centre of circle . If RS 14.14 then the area of shaded region