In the figure, RS ∥ DB ∥ PQ. If CP=PD=11cm and DR=RA=3cm. Then the values of x, y and z can be (A) 12, 10, 12 (B) 14, 6, 6 (C) 10, 7, 10 (D) 16, 8, 8 (A) 12, 10, 12 (B) 14, 6, 6 (C) 10, 7, 10 (D) 16, 8, 8 Share with your friends Share 10 Lovina Kansal answered this Dear student Given: RS∥DB∥PQ, CP=PD=11cm and DR=RA=3cmTo find: the value of x,y and z respectively.In △ASR and △ABD∠ASR=∠ABQ [Corresponding angles]∠A=∠A [common]∴△ASR~△ABD [AA similarity]⇒ARAD=ASAB=RSDB [By CPCT]⇒ARAD=RSDB⇒ARDR+RA=RSDB⇒36=RSDB⇒12=RSDB⇒12=yx⇒x=2yThis relation is satisfied by option d)Hence x=16,y=8 and z=8 Regards 11 View Full Answer