​​In the given figure, ABC is a right angled triangle. Semicircles are drawn on AB, AC and BC as diameters. If AB = 6 cm and AC = 8 cm, then find the area of the shaded region.   PLEASE SOLVE THIS QUESTION!   NOTE: In the following diagram, measurements have been given wrong.Please refer to question above for actual measurements!    

Area of shaded part = Area of both smaller semicircles + Area of triangle- Area of bigger semicircle
= 1/2 pi 3^2 + 1/2 pi 4^2  + 1/2 *8 *6 - 1/2 pi 5^2
 = 1/2 pi (9+16) - 1/2 pi (25)  +  1/2*8*6 
= 0 + 1/2 *8*6 = 4*6 = 24 cm^2
  • 0
for semi circle ABP,
area=1/2 * 22/7* 3* 3
=99/7
for ​semi circle ACQ,
area=1/2 * 22/7 * 4 * 4
=176/7
for ​triangle ABC,
area=1/2 * 8 * 6
=24
BC2=32+42
=25
BC=5
for ​semi circle ABC,
area=1/2 * 22/7 * 5/2 *5/2
=55/28

ar(shaded region)=ar(semicircle ABP)+ar(semicircle ACQ)+ar(triangle ABC)-ar(semicircle ABC)
=99/7+176/7+25-55/28
=1100+700-55
         28
=62.32 cm2
   
  • 0
What are you looking for?