In the given figure ABCDE is a pentagon whose vertices lie on semicircle with center O. Find sum of angle ACD and DEB 

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Please find below the solution to the asked query:
ACB=AEB=90°  angle made by diameter to the circumference is 90°In ACDE quadrilateral ACD+AED=180°And AED=AEB+DEB=90°+DEBSo ACD+90°+DEB=180°SoACD+DEB=180-90=90°    Answer

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