In the given figure AD bisects Angle-A​ and AD is perpendicular to BC. Prove that Angle-B= Angle-C.​​

Dear student
Consider ABD and ACDAD=AD common BAD=CAD  As AD bisects AADB=ADC=90°  as AD  BCSo ABDACD ASA criteriaSo, B=C C.P.C.T
Regards

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As AD bisects triangle ABC,
BD = DC
ANGLE ADB = ANGLE ADC  = 90 degrees
AD is the common arm
​ Therefore by SAS test triangle ADB = triangle ADC
​angle B = angle C as corresponding angles of congruent triangles


 
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