​In the given figure, AD is perpendicular to BC ,angle BEC =100 , angle DAC = 45, then find the values of x, y and z ? ( URGENT ANS PLS BY  EXPERTS )

Dear student
In ADC, By angle sum property of triangle,ADC+DAC+DCA=180°90°+45°+DCA=180°DCA=45°In BCE, By angle sum property of triangle, BCE+BEC+CBE=180°45°+100°+CBE=180°CBE=35°Let the point be O where BE and AD intersects.Then In BOD, By angle sum property of triangle,DBO+BDO+BOD=180°35°+90°+BOD=180°BOD=55° Now, z+BOD=180°    [Linear pair]z+55°=180°z=125°
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