In the given figure, angle A= angle C and AB =BC. Prove that triangle ABD is congruent to triangle CBE​

This is the question

Given, angleA=angleC AB=A.C. now,intriangle ABDandCBE AB=A.C. (GIVEN) angleA=angleC angleABD=angleCBE (COMMON) So by WAS triangleABDcongruent triangle CBE

Solve it

Given : angleA =angleC , AB = BC Prove : ∆ABD CONGRENT ∆CBE Proof : angleA = angleC (Given) AngleB = angleB. (common) AB = BC (Given) So ∆ ABD Congruent ∆CBE By (SAS) rule