in the given figure angle CAB : BAD = 1:2, find all the internal angles of triangle ABC.

We know that the sum of all angles of a triangle is 180.Therefore in triangle ABCABC+BCA+CAB=180x+x+13+CAB=180CAB=167-2xAlso,  CAB+DAE+BAD=180                    Supplementary angles167-2x+60+BAD=180BAD=2x-47Now, it is given thatCABBAD=12167-2x2x-47=12334-4x=2x-476x=381x=1272Hence, the angles of the triangle ABC areABC=x=1272BCA=x+13=1272+13=1532CAB=167-2x=167-21272=40.

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