In the given figure EB is perpendicular to AC, BG is perpendicular to AE and CF is perpendicular to AE. prove that triangle ABC is similar to triangle DCB also prove that BC/BD = BE/BA
In the last step you might get confused, after proving AEB triangle congruent to DCB, then by CPST,
First prove BC/BE=BD/BA,
THEN Criss multiply to get your answer.
I hope it helps you
