in the given figure,O is the center of the circle with radius 5cm.OP is perpendicular to AB,OQ is perpendicular to CD,AB=6cm and CD=8cm. determine PQ. Share with your friends Share 3 Varun.Rawat answered this We have, O as the centre of circle whose radius is 5 cm.AB and CD are two chord of a circle.AB = 6 cm; CD = 8 cm; OA = OD = 5 cmAlso, OP⊥AB and OQ⊥CD.We know that ⊥ drawn from the centre to the chord bisects the chord.So, AP = PB = AB2 = 3 cmand CQ = QD = CD2 = 4 cmIn ∆OPA, OP2 = OA2 - AP2 Pythagoras theorem⇒OP2 = 52-32⇒OP2 = 25 - 9⇒OP2 = 16⇒OP = 4 cmIn ∆OQD, OQ2 = OD2-QD2 Pythagoras theorem⇒OQ2 = 52-42⇒OQ2 = 25 - 16⇒OQ2 = 9⇒OQ = 3 cmNow, PQ = OP + OQ = 4 + 3 = 7 cm 3 View Full Answer Sanniddhya answered this Use the Pythagoras theorem on both the right angled triangles 3