In the given figure, O is the centre of a circle and ∠ADC = 130°. Find ∠BAC. Share with your friends Share 0 Global Expert answered this We know that ABCD is a cyclic quadrilateral.Hence, ∠B+∠D = 180°⇒∠B= 180°- ∠D⇒∠B= 180°-130°⇒∠B=50°In ∆ABC, ∠ABC+∠ACB+∠BAC=180° (Angle-sum property)⇒∠BAC=180° -∠ABC-∠ACB⇒∠BAC=180°-50°-90° (∠ACB =90°, as angle in a semi-circle is a right angle)⇒∠BAC=40° 0 View Full Answer