In the given figure, O is the centre of a circle and ADC = 130°. Find ∠BAC.

We know that ABCD is a cyclic quadrilateral.
Hence, B+D = 180°B= 180°- DB= 180°-130°B=50°

In ABC, ABC+ACB+BAC=180°  (Angle-sum property)BAC=180° -ABC-ACBBAC=180°-50°-90°  (ACB =90°, as angle in a semi-circle is a right angle)BAC=40°

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