In the given figure, triangle ABC similar to triangle PQR, AD perpendicular to BC, PS perpendicular to QR and AD : PS= 4 : 9. Find the ar.(ABC)/ar.(PQR)? Share with your friends Share 0 Rishabh Mittal answered this In ∆ABD and ∆PQS∠ABD=∠PQS Equal angles of similar triangles∠ADB=∠PSQ=90°By AA Similarity criterion△ABD~△PQSSo,ABPQ=ADPS=49As △ABC~△PQRarea△ABCarea△PQR=AB2PQ2=ABPQ2=492=1681 ANS... 3 View Full Answer