in the inverse spinel compound Fe3O4 the % of tetrahedral voids occupied =
a) 12.5 %
b) 50%
c) 74%
d) 68%

Question

in the inverse spinel compound Fe3O4 the % of tetrahedral voids
occupied =
a) 12 5 %
b) 50%
c) 74%
d) 68%

Yasodharan · Accepted Answer

Dear Student,

The compound Fe3O4 comprised of
Fe3+ and Fe2+ at the
ratio of 2:1 an inverse spinel expressed with correct formula as
(Fe3+)[Fe2+Fe3+]O4

Hence the tetrahedral void is (1/2) = 50 %

Answer is Option (B) 50%

Regards