in the meiotic cell division, 56 daughter cells are produced by two successive divisions in which 

(1) first division is equational, second is reductional 
(2) first division is reductional, and second is eqautional
​(3) both the divisions are reductional
(4) both the divisions are equational
 

Dear student.

The correct answer is 2.  First  division is reductional and second is equational.

14 diploid cell will undergo, meiosis 1(reductional) to form 28 haploid cells, those will undergo meiosis II (equational) division to form 56 haploid cells.
 

Meiosis: Meiosis is the reductional cell division in which diploid (double set) number of chromosomes is reduced to haploid (single set) number.

Meiosis has two different phases – meiosis I and meiosis II.

Meiosis I is reduction division which produces two haploid cells. The steps of meiosis I can be further differentiated as Prophase I, Metaphase I, Anaphase I, Telophase I.

Meiosis II is the equational division which produces total of four haploid cells from the two resulting meiosis I cells by the process of mitosis. During formation of male and female gametes in organisms meiosis occurs. The divisions of meiosis II are Prophase II, Metaphase II, Anaphase II and Telophase II.  


Regards.

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