In the synthesis of ammonia from nitrogen and hydrogen gases if 6×10^-2 mole of hydrogen disappears in 10 min the no. of moles of ammonia formed in 0.3 min is

Dear Student,

The reaction can be written as :
N2+3H22NH3Rate of dissapearance of hydrogen = Rate of appearance of ammoniaThus,13×6×10-210=12×nNH30.3So, nNH3=0.33×2×6×10-210=1.2 ×10-3

Thus, 1.2 mmol of ammonia are formed in 0.3 min.

Hope it helps.

Regards

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