in the triangle ABC, angle ABC=90degree,AB=2a+1 and BC=2a*a+2a.Find AC in terms of a.If a=8 find the lengths of the sides of the triangle ABC.

Dear Student,

 in a right angled triangle Given Side AB=2a+1BC=2a2+2a=2aa+1find ACUsing Pythagoras theoremAC2=AB2+BC2AC=AB2+BC2AC=2a+12+2aa+12AC=4a2+1+4a+4a2a2+1+2aAC=4a2+1+4a+4a4+4a2+8a3AC=4a+1+4a4+8a2+8a3Given If a=8thenAB=2a+1       =2×8+1AB =17 unitBC=2a2+2a       =2×82+2×8      =2×64+16       =128+16BC=144 unit AC=4a+1+4a4+8a2+8a3AC=4×8+1+4×84+8×82+8×83AC=32+1+16384+512+4096AC=21025AC=145unitAnswe   AC=4a+1+4a4+8a2+8a3  when a=8  ; AB=17unit , BC=144 unit, AC=145 unit


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