In the youngs double slit experiment using a monochromatic light of wavelength , the path difference corresponding to any point having half the peak intensity is Share with your friends Share 1 Udbhav Singh answered this Dear Student, According to Malus's Law I=4I0Cos2(φ/2)and Acc to question, I=2I02I0=4I0Cos2(φ/2)Cos2(φ/2)=1/2Cos(φ/2) = 1/2φ/2=π/4φ=π/2 Thus, Path Difference ∆x =λ2π×∆φ∆x =λ2π×π2∆x =λ4 Regards 0 View Full Answer