In this question, if I have to verify that pi/3 is the point of maxima via first derivative test then why does it give this as the point of minima??? 
Prove that pi/3 is the point of maxima via first derivative test???

Q.25 If the sum of lengths of the hypotenuse and a side of a right angles triangle is given, then show that the area of triangle is maximum, where the angle between them is  π 3 ,



Dear Student,

As per your query we are proving π3 is the point of maxima via first derivative test.So, We are providing you solution after putting dAdθ=0k22(1+cos θ)3(2 cos2θ+cos θ-1)=02 cos2θ+cos θ-1=02 cos2θ+2cos θ-cos θ-1=02 cos θ(cos θ+1)-1(cos θ+1)=0(cos θ+1)(2cos θ-1)=0either cos θ=-1 or cos θ=12either θ=π or θ=π3First Derivative TestHere we shall have three cases case 1 : θ<π3Take a value in this interval and check whether dAdθ is positive or negativefor convenient take θ=0.dAdθθ=0=k22(1+cos 0)3(2 cos20+cos 0-1)=k22(1+1)3(2×1+1-1)=k22(2)3×2=k28>0Positivecase 2 : π3<θ<πTake a value in this interval and check whether dAdθ is positive or negativefor convenient take θ=π2.dAdθθ=π2=k22(1+cos π2)3(2 cos2π2+cos π2-1)=k22(1+0)3(2×0+0-1)=k22(-1)=-k22<0Negativecase 1 : θ>πTake a value in this interval and check whether dAdθ is positive or negativefor convenient take θ=2π.dAdθθ=2π=k22(1+cos 2π)3(2 cos22π+cos 2π-1)=k22(1+1)3(2×1+1-1)=k22(2)3×2=k28>0PositiveSo, at π3 slope (dAdθ) is changing from Positive to negativeMaxima at π3 .So, at π slope (dAdθ) is changing from Negative to PositiveMinima at π .
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