in this question the total pressure is 50 atm. we have to find  the pressure at which 50% dissociation occurs at the same temperature

Dear Student,

                   PCl 5      PCl3   + Cl2Initial            1                   0             0At time t     1-x                x             xGiven, x=0.25 at 50 atm pressureKp= (nPCl3nCl2nCl5)(Pn)n     =((x)(x)(1-x))(P1+x)1     =P(x)2(1-x2)     =(0.25)2(50)1-(0.25)2     =3.33 atmWhen x=0.50, Kp remaining constantKp=P(x)2(1-x2)3.33=(0.50)2(P)1-(0.50)2or, P= 10 atmHence, correct answer is (A)

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