in this question the total pressure is 50 atm. we have to find the pressure at which 50% dissociation occurs at the same temperature Share with your friends Share 1 Vartika Jain answered this Dear Student, PCl 5 ↔ PCl3 + Cl2Initial 1 0 0At time t 1-x x xGiven, x=0.25 at 50 atm pressureKp= (nPCl3nCl2nCl5)(P∑n)∆n =((x)(x)(1-x))(P1+x)1 =P(x)2(1-x2) =(0.25)2(50)1-(0.25)2 =3.33 atmWhen x=0.50, Kp remaining constantKp=P(x)2(1-x2)3.33=(0.50)2(P)1-(0.50)2or, P= 10 atmHence, correct answer is (A) 0 View Full Answer