In triangle AB=AC and ad perpendicular to BC prove that D is the midpoint of BC



In ADB and ADCADB = ADC    90° each        AB = AC     Given        AD = AD      CommonSo, ADBADC   RHS

  • 1
FROM WHICH TEXT BOOK
  • 0
WHAT IS ad?
  • 0
We can answer this question by applying the theory of congruency
Here in Triangle ABD and Triangle ADC
AD = AD (SIDE ) -  COMMON
Angle ADB = Angle ADC (ANGLE) - PERPENDICULAR BISECTOR
AB = AC (SIDE) - GIVEN
Hence Triangle ABD is congruent to triangle ADC.
Hence, bd = dc by common parts of congruent triangles.
Hence proven
  • 1
in triangle from where the 4th side came
  • -1
What are you looking for?