# In triangle ABC,AB=AC and angle B=50.then angle C is equal to

^{o }then A= 50

^{o}

let C be x

By applying the angle sum property,

x+50+50=180

x+100=180

x=180-100

x=80

^{o}

So, C=80

^{o}

let C be x

By applying the angle sum property,

x+50+50=180

x+100=180

x=180-100

x=80

So, C=80

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