In triangle ABC, AD is a median . Prove that AB2 + AC2 = 2(AD2 + BD2 )

Hi!
Here is the answer to your question.
 
Given: AD is median. So BD = DC
Construction: Draw AE⊥ BC
To prove: AB2 + AC2 = 2 (AD2 + BD2)
Proof:
In ∆AED,
 
 
Cheers!

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