In triangle ABC , AM is perpendicular to BC and AN is the bisector of angle A. Find the measure of angle MAN, when angle B = 65 degree and angle C = 30 degree.

Since ∠A + ∠B + ∠C = 180°

⇒ ∠A = 85°

Also, AN is angle bisector of ∠BAC

∴ ∠BAN = ∠NAC =

As ∠ANC is exterior angle of Δ ABN

Since BC is a straight line

⇒ ∠ANB + ∠ANC = 180°

In right  ΔAMN,

∠MAN + ∠ANM + ∠AMN = 180°

⇒ ∠MAN + ∠ANB + ∠AMN = 180°

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