1. In triangle ABC,angle BAC =110 degree.Q and R are points on the line BC and P is apoint such tha PQ is parallel to BA.Find angle QPR if angle CPR = 30 degree

Dear student,


Since ABPQBAC=CPQ   ---(corresponding angles)CPQ=110°But CPQ=x+30°110°=x+30°x=110°-30°x=80°thus, QPR=x=80°
Regards

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