In triangle ABC,angleA=50degree and BC is produced to a point D. The bisectors of angleABC and angleACD meet at E. Find angle E

In ∆ABC, BE is the interior angle bisector of ∠B and CE is the exterior angle bisector of ∠C.

Now In ΔABC

∠A + ∠B + ∠C = 180°

⇒ ∠A = 180° – x – y .... (1)

Now in ΔBCE,

ÐB = ,


ÐC = y +

And ÐB + ÐC + ÐE = 180°

From (1) and (2)

Þ ÐE = 25°

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25 degrees

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